本文由本人@takooctopus对LeetCode每日打卡签到，做点记录。
833. Find And Replace in String 「Medium」
题目描述:
To some string S, we will perform some replacement operations that replace groups of letters with new ones (not necessarily the same size).
Each replacement operation has 3 parameters: a starting index i, a source word x and a target word y. The rule is that if x starts at position i in the original string S, then we will replace that occurrence of x with y. If not, we do nothing.
For example, if we have S = "abcd" and we have some replacement operation i = 2, x = "cd", y = "ffff", then because “cd” starts at position 2 in the original string S, we will replace it with "ffff".
Using another example on S = "abcd", if we have both the replacement operation i = 0, x = "ab", y = "eee", as well as another replacement operation i = 2, x = "ec", y = "ffff", this second operation does nothing because in the original string S[2] = 'c', which doesn’t match x[0] = 'e'.
All these operations occur simultaneously. It’s guaranteed that there won’t be any overlap in replacement: for example, S = "abc", indexes = [0, 1], sources = ["ab","bc"] is not a valid test case.
| Example 1: |
|---|
Input: S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"] |
Output: "eeebffff" |
Explanation: "a" starts at index 0 in S, so it’s replaced by "eee"."cd" starts at index 2 in S, so it’s replaced by "ffff". |
| Example 2: |
|---|
Input: S = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"] |
Output: "eeecd" |
Explanation: "ab" starts at index 0 in S, so it’s replaced by "eee". "ec" doesn’t starts at index 2 in the original S, so we do nothing. |
Notes:
| Notes: |
|---|
| 0 <= indexes.length = sources.length = targets.length <= 100 |
| 0 < indexes[i] < S.length <= 1000 |
| All characters in given inputs are lowercase letters. |
Solution
由于我所接触的语言问题，这里我仅试了几种语言